Chapter 0 – Steady-State Hydraulics
Surge Analysis and the Wave Plan Method
Supplementary Material: Example Problems and Solutions
Chapter 0 – Problem 0.22
0.22 Consider a typical drinking water distribution network shown in the following figure (consider only the zoomed-in, looped portion of the system).
The arrows next to the pipe sections indicate the flow direction during steady-state operating conditions. The associated friction headlosses in pipes 1, 2, 3, and 4 are 1.05 m, 0.15 m, 0.45 m, and 0.25 m, respectively. What is the frictional headloss in pipe 5?
Solution:
An energy equation may be written for the loop starting at node C, traversing through pipes 1, 2, 3, 4, and 5 (in that sequence), and ending at the start of the loop (i.e., at, and including, node C). This can be written as:
EC – ΔH1 – ΔH2 + ΔH3 + ΔH4 + ΔH5 = EC. In this equation, the ΔH term will be subtracted from the left-hand side if the flow in the associated pipe section is in the same direction as the traversing direction of the loop shown in the figure above, and will be added if the flow is in the opposite direction.
The only unknown in the above equation is ΔH5:
ΔH5 = +0.5 m
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