Chapter 0 – Steady-State Hydraulics
Surge Analysis and the Wave Plan Method
Supplementary Material: Example Problems and Solutions
Chapter 0 – Problem 0.18
0.18 What is the resultant steady-state flowrate if there is a partially-throttled gate valve with a minor loss coefficient of 20 located close to reservoir B in the pipeline described in the previous question 0.17?
Solution:
The energy equation described in the previous question is altered by adding the minor loss term associated with the partially-throttled gate valve:
EA + EP – ΔH – kV2/(2g) = EB, where V is the pipe flow velocity and k is the minor loss coefficient of the partially-throttled gate valve.
If A is the pipe cross sectional area, then V = Q/A. A = 0.196 m2, for the given pipe diameter of 500 mm.
50 + 10.194/Q – (10.67 LQ1.852)/(C1.852 D4.87) – 20*Q2 / (2g A2) = 100
Solve for Q iteratively: Q = 0.165 m3/s
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